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Popular >

4y^'-e^{3x}y=0

Solution

4 y^{^{'}} - e^{3 x} y = 0

Solution

y = e^{\frac{e ^{3 x}}{12} + c_{1}}

Solution steps

4 y^{'} (x) - e^{3 x} y = 0

Solve separable ODE:

y = e^{\frac{e ^{3 x}}{12} + c_{1}}

y = e^{\frac{e ^{3 x}}{12} + c_{1}}

Graph

Popular Examples

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x^{2} (x + 1) (2 x^{2} - x - 5) d x = \frac{1}{( y + 1 )} d y

(dy)/(dx)y=(2x+1)/(xsin(x))

\frac{d y}{d x} y = \frac{2 x + 1}{x sin ( x )}

y^{^{'}} - b y = 2

Frequently Asked Questions (FAQ)

What is the solution for 4y^'-e^{3x}y=0 ?
The solution for 4y^'-e^{3x}y=0 is y=e^{(e^{3x})/(12)+c_{1}}