What is the solution for (dy)/(dx)y=u^2,u=5x-1 ?

The solution for (dy)/(dx)y=u^2,u=5x-1 is y=sqrt(2u^2x+c_{1)},y=-sqrt(2u^2x+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)y=u^2,u=5x-1

\frac{d y}{d x} y = u^{2}, u = 5 x - 1

y = 2 u^{2} x + c_{1}, y = - 2 u^{2} x + c_{1}

Solution steps

\frac{d y}{d x} y = u^{2}

Solve separable ODE:

y = 2 u^{2} x + c_{1}, y = - 2 u^{2} x + c_{1}

y = 2 u^{2} x + c_{1}, y = - 2 u^{2} x + c_{1}

\frac{\frac{1}{y} \frac{d y}{d x}}{( - 1 + y )} = - x

(x + x y^{2}) d x - 4 y d y = 0, y (1) = 0

y^{^{'}} + y cos (x) = 7 cos (x)

\frac{d y}{d x} = - \frac{4}{6} x^{6} y^{4}

v \frac{d v}{d x} = - 475000 - 5 v^{2}

What is the solution for (dy)/(dx)y=u^2,u=5x-1 ?
The solution for (dy)/(dx)y=u^2,u=5x-1 is y=sqrt(2u^2x+c_{1)},y=-sqrt(2u^2x+c_{1)}