What is (\partial)/(\partial x)(sqrt(2x^2-5y^2)) ?

The answer to (\partial)/(\partial x)(sqrt(2x^2-5y^2)) is (2x)/(sqrt(2x^2-5y^2))

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(\partial)/(\partial x)(sqrt(2x^2-5y^2))

\frac{\partial}{\partial x} (2 x^{2} - 5 y^{2})

\frac{2 x}{2 x ^{2} - 5 y ^{2}}

Solution steps

\frac{\partial}{\partial x} (2 x^{2} - 5 y^{2})

Treat

y

as a constant

Apply the chain rule:

\frac{1}{2 2 x ^{2} - 5 y ^{2}} \frac{\partial}{\partial x} (2 x^{2} - 5 y^{2})

= \frac{1}{2 2 x ^{2} - 5 y ^{2}} \frac{\partial}{\partial x} (2 x^{2} - 5 y^{2})

\frac{\partial}{\partial x} (2 x^{2} - 5 y^{2}) = 4 x

= \frac{1}{2 2 x ^{2} - 5 y ^{2}} \cdot 4 x

Simplify

\frac{1}{2 2 x ^{2} - 5 y ^{2}} \cdot 4 x : \frac{2 x}{2 x ^{2} - 5 y ^{2}}

= \frac{2 x}{2 x ^{2} - 5 y ^{2}}

\int_{- 2}^{6} 4 x - x^{2} + 12 d x

\int_{5}^{7} [\frac{k}{2} x^{2}] d x

y^{^{''}} + 5 y^{^{'}} = e^{- t}, y (0) = 0, y^{^{'}} (0) = 1

\frac{\partial}{\partial y} (e^{x y} ln (z))

\int \frac{( ln ( 2 x ) )}{x} d x

What is (\partial)/(\partial x)(sqrt(2x^2-5y^2)) ?
The answer to (\partial)/(\partial x)(sqrt(2x^2-5y^2)) is (2x)/(sqrt(2x^2-5y^2))