What is the solution for (dx)/(dt)=0.08-(0.15x)/(50),t=18 ?

The solution for (dx)/(dt)=0.08-(0.15x)/(50),t=18 is x=-(e^{-0.003t-c_{1}})/(0.15)+4/(0.15)

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(dx)/(dt)=0.08-(0.15x)/(50),t=18

\frac{d x}{d t} = 0.08 - \frac{0.15 x}{50}, t = 18

x = - \frac{e ^{- 0.003 t - c_{1}}}{0.15} + \frac{4}{0.15}

Solution steps

\frac{d x}{d t} = 0.08 - \frac{0.15 x}{50}

Solve separable ODE:

x = - \frac{e ^{- 0.003 t - c_{1}}}{0.15} + \frac{4}{0.15}

x = - \frac{e ^{- 0.003 t - c_{1}}}{0.15} + \frac{4}{0.15}

\frac{d y}{d x} = \frac{( 4 x e ^{x^{2}} )}{y}, y (0) = 3

\frac{d y}{d x} = - y (x^{2} - 7)

\frac{1}{y} \cdot \frac{d y}{d t} = 0.02

y \frac{d x}{d y} - x = 2, y^{2} y (1) = 5

y^{^{'}} + \frac{1}{2} (x - 2) y^{2} = 0, y (\frac{1}{10}) = 6

What is the solution for (dx)/(dt)=0.08-(0.15x)/(50),t=18 ?
The solution for (dx)/(dt)=0.08-(0.15x)/(50),t=18 is x=-(e^{-0.003t-c_{1}})/(0.15)+4/(0.15)