What is the solution for yy^'=4sin(x) ?

The solution for yy^'=4sin(x) is y=sqrt(-8cos(x)+c_{1)},y=-sqrt(-8cos(x)+c_{1)}

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yy^'=4sin(x)

y y^{^{'}} = 4 sin (x)

y = - 8 cos (x) + c_{1}, y = - - 8 cos (x) + c_{1}

Solution steps

y y^{'} (x) = 4 sin (x)

Solve separable ODE:

y = - 8 cos (x) + c_{1}, y = - - 8 cos (x) + c_{1}

y = - 8 cos (x) + c_{1}, y = - - 8 cos (x) + c_{1}

2500 \cdot \frac{d x}{d y} + 2875 \cdot x = 0, x (0) = 8.5

\frac{d y}{d x} y = 2 ln (3 + x^{2})

t \cdot \frac{d y}{d t} = - y \cdot (1 + 2 t^{2})

e^{x} \cdot cos (y) d x + (1 + e^{x}) \cdot sin (y) d y = 0

y^{^{'}} = 5 x^{2} y + y

What is the solution for yy^'=4sin(x) ?
The solution for yy^'=4sin(x) is y=sqrt(-8cos(x)+c_{1)},y=-sqrt(-8cos(x)+c_{1)}