What is the solution for (dt)/(dy)=2t*y^2 ?

The solution for (dt)/(dy)=2t*y^2 is y=\sqrt[3]{(3ln(t)+c_{1})/2}

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(dt)/(dy)=2t*y^2

\frac{d t}{d y} = 2 t \cdot y^{2}

y = 3 \frac{3 ln ( t ) + c _{1}}{2}

Solution steps

\frac{d}{d y} (t) = 2 t \cdot y^{2}

Solve separable ODE:

y = 3 \frac{3 ln ( t ) + c _{1}}{2}

y = 3 \frac{3 ln ( t ) + c _{1}}{2}

7 x y (\frac{d y}{d x}) = 4

\frac{d x}{d t} = \frac{2}{x}, x (0) = 8

y^{^{'}} sec (t) = \frac{- y ^{21}}{20}

sin (y) \cdot cos (x) \cdot y^{^{'}} = - cos (y) \cdot sin (x)

y^{^{'}} (t) = \frac{1}{8} y (1 - \frac{y}{8}), y (0) = 60

What is the solution for (dt)/(dy)=2t*y^2 ?
The solution for (dt)/(dy)=2t*y^2 is y=\sqrt[3]{(3ln(t)+c_{1})/2}