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Popular >

2y(y^')=6t^2,y(0)=5

Solution

2 y (y^{^{'}}) = 6 t^{2}, y (0) = 5

Solution

y = 2 t^{3} + 25

Solution steps

2 y (y^{'} (t)) = 6 t^{2}

Solve separable ODE:

y = 2 t^{3} + 25

y = 2 t^{3} + 25

Graph

Popular Examples

P^'=0.05P(1-P/(400))

P^{^{'}} = 0.05 P (1 - \frac{P}{400})

y=5(sin^2(x))y^'

y = 5 (sin^{2} (x)) y^{^{'}}

(dx)/(dy)=|(y-8)/(y-8)|x^{15}

\frac{d x}{d y} = \frac{y - 8}{y - 8} x^{15}

(dy)/(dx)=ky+50

\frac{d y}{d x} = k y + 50

(dp)/(dx)=\sqrt[7]{p/x}

\frac{d p}{d x} = 7 \frac{p}{x}

Frequently Asked Questions (FAQ)

What is the solution for 2y(y^')=6t^2,y(0)=5 ?
The solution for 2y(y^')=6t^2,y(0)=5 is y=sqrt(2t^3+25)