What is the solution for y^'=(4(1+x))/(xy) ?

The solution for y^'=(4(1+x))/(xy) is y=sqrt(8(ln(x)+x)+c_{1)},y=-sqrt(8(ln(x)+x)+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=(4(1+x))/(xy)

y^{^{'}} = \frac{4 ( 1 + x )}{x y}

y = 8 (ln (x) + x) + c_{1}, y = - 8 (ln (x) + x) + c_{1}

Solution steps

y^{'} (x) = \frac{4 ( 1 + x )}{x y}

Solve separable ODE:

y = 8 (ln (x) + x) + c_{1}, y = - 8 (ln (x) + x) + c_{1}

y = 8 (ln (x) + x) + c_{1}, y = - 8 (ln (x) + x) + c_{1}

y^{^{'}} = \frac{tan ( x )}{y}, y (0) = - 1

\frac{d y}{d x} = \frac{1 - x}{2 + y}

\frac{d y}{d x} = e^{2 x + 2 y}

\frac{d y}{d x} = \frac{2 y}{x - 1}

\frac{d y}{d x} = - \frac{2 x}{6 y}

What is the solution for y^'=(4(1+x))/(xy) ?
The solution for y^'=(4(1+x))/(xy) is y=sqrt(8(ln(x)+x)+c_{1)},y=-sqrt(8(ln(x)+x)+c_{1)}