What is the solution for (dy)/(dx)=(3xy)/((ln(y))^4) ?

The solution for (dy)/(dx)=(3xy)/((ln(y))^4) is y=e^{\sqrt[5]{(15x^2+c_{1})/2}}

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(dy)/(dx)=(3xy)/((ln(y))^4)

\frac{d y}{d x} = \frac{3 x y}{( ln ( y ) ) ^{4}}

y = e^{5 \frac{15 x ^{2} + c _{1}}{2}}

Solution steps

\frac{d y}{d x} = \frac{3 x y}{( ln ( y ) ) ^{4}}

Solve separable ODE:

y = e^{5 \frac{15 x ^{2} + c _{1}}{2}}

y = e^{5 \frac{15 x ^{2} + c _{1}}{2}}

y^{^{'}} = \frac{2 y}{5 x}

\frac{d y}{d x} x = e^{x} (y - 1)

\frac{d v}{d t} = 14 - 1.4 v

\frac{d y}{d x} = 6 x^{2} y, y > 0

(1 + y) (\frac{d y}{d x}) + sin^{2} (x) = 1

What is the solution for (dy)/(dx)=(3xy)/((ln(y))^4) ?
The solution for (dy)/(dx)=(3xy)/((ln(y))^4) is y=e^{\sqrt[5]{(15x^2+c_{1})/2}}