What is the solution for (dx)/(dy)x^3+y^3=3 ?

The solution for (dx)/(dy)x^3+y^3=3 is x=\sqrt[4]{12y-y^4+c_{1}},x=-\sqrt[4]{12y-y^4+c_{1}}

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(dx)/(dy)x^3+y^3=3

\frac{d x}{d y} x^{3} + y^{3} = 3

x = 4 12 y - y^{4} + c_{1}, x = - 4 12 y - y^{4} + c_{1}

Solution steps

\frac{d x}{d y} x^{3} + y^{3} = 3

Solve separable ODE:

x = 4 12 y - y^{4} + c_{1}, x = - 4 12 y - y^{4} + c_{1}

x = 4 12 y - y^{4} + c_{1}, x = - 4 12 y - y^{4} + c_{1}

x \cdot y^{^{'}} = (1 - y^{2})^{\frac{1}{2}}

\frac{d y}{d x} = (1 - 13 x) y^{2}

\frac{d r}{d s} = 0.09 r

(1 + e^{x}) \frac{d y}{d x} = \frac{e ^{x}}{y}

\frac{d y}{d x} = x y + x - 2 y - 2, a y (0) = 2

What is the solution for (dx)/(dy)x^3+y^3=3 ?
The solution for (dx)/(dy)x^3+y^3=3 is x=\sqrt[4]{12y-y^4+c_{1}},x=-\sqrt[4]{12y-y^4+c_{1}}