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Popular >

x^'+x/(50)=2

Solution

x^{^{'}} + \frac{x}{50} = 2

Solution

x = - e^{\frac{- t - c _{1}}{50}} + 100

Solution steps

x^{'} (t) + \frac{x}{50} = 2

Solve separable ODE:

x = - e^{\frac{- t - c _{1}}{50}} + 100

x = - e^{\frac{- t - c _{1}}{50}} + 100

Graph

Popular Examples

xy^'cos(y)+sin(y)=0

x y^{^{'}} cos (y) + sin (y) = 0

(1+x^2)y^'-2x(y+3)=0

(1 + x^{2}) y^{^{'}} - 2 x (y + 3) = 0

\frac{d y}{d x} = y + 7

(dx)/(dt)=14-0.28*x

\frac{d x}{d t} = 14 - 0.28 \cdot x

(dx)/(dt)=(8*10^{-3})/(100)-8 x/(9500)

\frac{d x}{d t} = \frac{8 \cdot 1 0 ^{- 3}}{100} - 8 \frac{x}{9500}

Frequently Asked Questions (FAQ)

What is the solution for x^'+x/(50)=2 ?
The solution for x^'+x/(50)=2 is x=-e^{(-t-c_{1})/(50)}+100