What is the solution for y^'=x^22^y ?

The solution for y^'=x^22^y is y=-(ln(-(ln(2)x^3)/3-c_{1}))/(ln(2))

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y^'=x^22^y

y^{^{'}} = x^{2} 2^{y}

y = - \frac{ln ( - \frac{l n ( 2 ) x ^{3}}{3} - c _{1} )}{ln ( 2 )}

Solution steps

y^{'} (x) = x^{2} 2^{y}

Solve separable ODE:

y = - \frac{ln ( - \frac{l n ( 2 ) x ^{3}}{3} - c _{1} )}{ln ( 2 )}

y = - \frac{ln ( - \frac{l n ( 2 ) x ^{3}}{3} - c _{1} )}{ln ( 2 )}

10 y^{^{'}} + 5 y = 0

(3 x^{2} + 2)^{3} y^{^{'}} - x y^{2} = 0, y (0) = 2

\frac{d y}{d x} y = 8 x arcsin (x)

cos (x) y^{^{'}} - tan (x) y = 0

\frac{d x}{d y ( y )} = e^{- x}

What is the solution for y^'=x^22^y ?
The solution for y^'=x^22^y is y=-(ln(-(ln(2)x^3)/3-c_{1}))/(ln(2))