What is the solution for h'+(0.18h^{(-3)/2}) 1/pi =0 ?

The solution for h'+(0.18h^{(-3)/2}) 1/pi =0 is h(t)=(-0.14323…t-c_{1})^{2/5}

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h'+(0.18h^{(-3)/2}) 1/pi =0

h^{^{'}} + (0.18 h^{\frac{- 3}{2}}) \frac{1}{π} = 0

h (t) = (- 0.14323 \dots t - c_{1})^{\frac{2}{5}}

Solution steps

h^{'} (t) + (0.18 h (t)^{\frac{- 3}{2}}) \frac{1}{π} = 0

Solve separable ODE:

h (t) = (- 0.14323 \dots t - c_{1})^{\frac{2}{5}}

h (t) = (- 0.14323 \dots t - c_{1})^{\frac{2}{5}}

(csc (y)) d x + cos^{2} (x) d y = 0

(3 x - 2) \frac{d y}{d x} = (6 x - 1) y

(x^{2} + 36) y^{^{'}} + x y = x

\frac{d y}{d x} = - \frac{( x - 8 )}{64 y - 320}

csc (y) + sec^{2} (x) \frac{d y}{d x} = 0

What is the solution for h'+(0.18h^{(-3)/2}) 1/pi =0 ?
The solution for h'+(0.18h^{(-3)/2}) 1/pi =0 is h(t)=(-0.14323…t-c_{1})^{2/5}