What is the tangent of f(x)=x^2+6,(1,7) ?

The tangent of f(x)=x^2+6,(1,7) is y=2x+5

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tangent of f(x)=x^2+6,(1,7)

tangent of

f (x) = x^{2} + 6, (1, 7)

y = 2 x + 5

Solution steps

Find the slope of

f (x) = x^{2} + 6 : \frac{df ( x )}{d x} = 2 x

Compute the slope of

f (x) = x^{2} + 6

(1, 7) : m = 2

Find the line with slope m=

2

and passing through

(1, 7) : y = 2 x + 5

y = 2 x + 5

\int csc^{6} (x) d x

\frac{( 1 - v )}{( 1 + v )}

\frac{d y}{d x} = \frac{1}{3} x (y - 2)^{2}

n = 0 \sum \infty 9

f (x) = (0.001 + 2)^{0.001}

What is the tangent of f(x)=x^2+6,(1,7) ?
The tangent of f(x)=x^2+6,(1,7) is y=2x+5