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Popular >

y+y^'x=0

Solution

y + y^{^{'}} x = 0

Solution

y = \frac{c _{1}}{x}

Solution steps

y + y^{'} (x) x = 0

Solve separable ODE:

y = \frac{c _{1}}{x}

y = \frac{c _{1}}{x}

Graph

Popular Examples

gx^'=sqrt(2x-9)

g x^{^{'}} = 2 x - 9

y^{^{'}} = 5 x y^{6}

7sqrt(y)dy= 3/(sqrt(x))dx

7 y d y = \frac{3}{x} d x

sqrt(x^2+6)dx-1/(xcsc(-8y))dy=0

x^{2} + 6 d x - \frac{1}{x csc ( - 8 y )} d y = 0

y^'=(y(y-2))/(x(y-1))

y^{^{'}} = \frac{y ( y - 2 )}{x ( y - 1 )}

Frequently Asked Questions (FAQ)

What is the solution for y+y^'x=0 ?
The solution for y+y^'x=0 is y=(c_{1})/x