What is the solution for 2((dq)/(dt))+6q=2 ?

The solution for 2((dq)/(dt))+6q=2 is q=-(e^{-3t-c_{1}})/3+1/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2((dq)/(dt))+6q=2

2 (\frac{d q}{d t}) + 6 q = 2

q = - \frac{e ^{- 3 t - c_{1}}}{3} + \frac{1}{3}

Solution steps

2 (\frac{d q}{d t}) + 6 q = 2

Solve separable ODE:

q = - \frac{e ^{- 3 t - c_{1}}}{3} + \frac{1}{3}

q = - \frac{e ^{- 3 t - c_{1}}}{3} + \frac{1}{3}

\frac{2 x}{a ^{2}} + \frac{2 y \frac{d y}{d x}}{b ^{2}} = 0

\frac{d y}{d x} = - \frac{2 x}{3 y}

\frac{d y}{d x} = \frac{sin ( x )}{3 y}

x^{^{'}} - 5 x = 0

2 x (1 + y^{2}) d x - y (1 - 2 x^{2}) d y = 0

What is the solution for 2((dq)/(dt))+6q=2 ?
The solution for 2((dq)/(dt))+6q=2 is q=-(e^{-3t-c_{1}})/3+1/3