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Popular >

x+yxdx-dy=0

Solution

x + y x d x - d y = 0

Solution

y = e^{\frac{x ^{2}}{2} + c_{1}} - 1

Solution steps

x + y x d x - d y = 0

Solve separable ODE:

y = e^{\frac{x ^{2}}{2} + c_{1}} - 1

y = e^{\frac{x ^{2}}{2} + c_{1}} - 1

Popular Examples

(dy}{dx}=\frac{y^{1/2}ln(x))/x

\frac{d y}{d x} = \frac{y ^{\frac{1}{2}} ln ( x )}{x}

(dy)/(dt)=k(y-2)

\frac{d y}{d t} = k (y - 2)

y^'=((xy+3y))/(x-3)

y^{^{'}} = \frac{( x y + 3 y )}{x - 3}

derivative of ln(y)= 1/3 ln(x^2-9)

\frac{d}{d x} (ln (y)) = \frac{1}{3} ln (x^{2} - 9)

y^'=sin(x)sin(y)

y^{^{'}} = sin (x) sin (y)

Frequently Asked Questions (FAQ)

What is the solution for x+yxdx-dy=0 ?
The solution for x+yxdx-dy=0 is y=e^{(x^2)/2+c_{1}}-1