What is the solution for y^'=y^{-9}x^9,y(0)=9 ?

The solution for y^'=y^{-9}x^9,y(0)=9 is y=\sqrt[10]{x^{10}+9^{10}}

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y^'=y^{-9}x^9,y(0)=9

y^{^{'}} = y^{- 9} x^{9}, y (0) = 9

Solution steps

y^{'} (x) = y^{- 9} x^{9}

Solve separable ODE:

\frac{x}{100} + \frac{d x}{d t} = 10

\frac{d y}{d x} = - 12 x^{3} y

y^{^{'}} = b \cdot y + c

8 x - 5 y x^{2} + 1 \frac{d y}{d x} = 0, y (0) = - 10

(x tan (x)) d x - (y cos (x)) d y = 0

What is the solution for y^'=y^{-9}x^9,y(0)=9 ?
The solution for y^'=y^{-9}x^9,y(0)=9 is y=\sqrt[10]{x^{10}+9^{10}}