What is the solution for (dy)/(dx)=xe^{y-x} ?

The solution for (dy)/(dx)=xe^{y-x} is y=-ln(e^{-x}x+e^{-x}-c_{1})

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(dy)/(dx)=xe^{y-x}

\frac{d y}{d x} = x e^{y - x}

y = - ln (e^{- x} x + e^{- x} - c_{1})

Solution steps

\frac{d y}{d x} = x e^{y - x}

Solve separable ODE:

y = - ln (e^{- x} x + e^{- x} - c_{1})

y = - ln (e^{- x} x + e^{- x} - c_{1})

\frac{d y}{d x} = 10 x 36 - y^{2}, y > - 6, y < 6

y^{^{'}} = - 0.7 y, y (0) = 80

\frac{d v}{d t} = 50 - \frac{9 v}{100}

\frac{d y}{d x} = (5 y + 8)^{\frac{2}{3}}

\frac{d x}{d t} = 2 x + x

What is the solution for (dy)/(dx)=xe^{y-x} ?
The solution for (dy)/(dx)=xe^{y-x} is y=-ln(e^{-x}x+e^{-x}-c_{1})