What is the solution for y^'= pi/y ?

The solution for y^'= pi/y is y=sqrt(2pit+c_{1)},y=-sqrt(2pit+c_{1)}

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y^'= pi/y

y^{^{'}} = \frac{π}{y}

y = 2 π t + c_{1}, y = - 2 π t + c_{1}

Solution steps

y^{'} (t) = \frac{π}{y}

Solve separable ODE:

y = 2 π t + c_{1}, y = - 2 π t + c_{1}

y = 2 π t + c_{1}, y = - 2 π t + c_{1}

\frac{d y}{d x} = - \frac{sin ( x + 5 )}{y}

- x \cdot f (x) = \frac{df}{d x}

\frac{d x}{d t} = \frac{t + sin ^{2} ( t )}{x}, x (0) = 1

\frac{d y}{d x} = 0.9 (y - 300)

\frac{d y}{1} = \frac{d x}{1 + y}

What is the solution for y^'= pi/y ?
The solution for y^'= pi/y is y=sqrt(2pit+c_{1)},y=-sqrt(2pit+c_{1)}