What is the limit as x approaches infinity of e^{-8x^2} ?

The limit as x approaches infinity of e^{-8x^2} is 0

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limit as x approaches infinity of e^{-8x^2}

x \to \infty lim (e^{- 8 x^{2}})

0

Solution steps

x \to \infty lim (e^{- 8 x^{2}})

Apply the Limit Chain Rule:

0

= 0

y = (x - 2)^{2}, y = 2 x - 1

\frac{\partial}{\partial x} (5 x^{2} y^{3})

\int \frac{1}{( x ^{2} + 4 )} d x

\int \frac{( 2 x + 5 )}{x ^{2} + 5 x} d x

What is the limit as x approaches infinity of e^{-8x^2} ?
The limit as x approaches infinity of e^{-8x^2} is 0