What is the solution for y^'=((cos^2(x)))/y ?

The solution for y^'=((cos^2(x)))/y is y=sqrt((2x+sin(2x)+c_{1))/2},y=-sqrt((2x+sin(2x)+c_{1))/2}

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y^'=((cos^2(x)))/y

y^{^{'}} = \frac{( cos ^{2} ( x ) )}{y}

y = \frac{2 x + sin ( 2 x ) + c _{1}}{2}, y = - \frac{2 x + sin ( 2 x ) + c _{1}}{2}

Solution steps

y^{'} (x) = \frac{( cos ^{2} ( x ) )}{y}

Solve separable ODE:

y = \frac{2 x + sin ( 2 x ) + c _{1}}{2}, y = - \frac{2 x + sin ( 2 x ) + c _{1}}{2}

y = \frac{2 x + sin ( 2 x ) + c _{1}}{2}, y = - \frac{2 x + sin ( 2 x ) + c _{1}}{2}

y^{^{'}} = \frac{y + 5}{7 t + 50}, y (2) = 0

4 x y^{^{'}} - 3 = y^{2} + 2

(1 + x) \frac{d y}{d x} = e^{- y} - 1

\frac{1500}{230} (1 - 30 x^{^{'}}) = \frac{x}{0.1} + 75 x^{^{'}}

y^{^{'}} + a y + \frac{2 \cdot y}{x} = 0

What is the solution for y^'=((cos^2(x)))/y ?
The solution for y^'=((cos^2(x)))/y is y=sqrt((2x+sin(2x)+c_{1))/2},y=-sqrt((2x+sin(2x)+c_{1))/2}