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Popular >

y^'+y/4 =4,y(-3)=0

Solution

y^{^{'}} + \frac{y}{4} = 4, y (- 3) = 0

Solution

y = - 16 e^{\frac{- t - 3}{4}} + 16

Solution steps

y^{'} (t) + \frac{y}{4} = 4

Solve separable ODE:

y = - 16 e^{\frac{- t - 3}{4}} + 16

y = - 16 e^{\frac{- t - 3}{4}} + 16

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Frequently Asked Questions (FAQ)

What is the solution for y^'+y/4 =4,y(-3)=0 ?
The solution for y^'+y/4 =4,y(-3)=0 is y=-16e^{(-t-3)/4}+16