What is the solution for (dy)/(dx)x^2-y+y^2=-3 ?

The solution for (dy)/(dx)x^2-y+y^2=-3 is y=(tan(-(sqrt(11)(-1+c_{1}x))/(2x))sqrt(11))/2+1/2

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(dy)/(dx)x^2-y+y^2=-3

\frac{d y}{d x} x^{2} - y + y^{2} = - 3

y = \frac{tan ( - \frac{11 ( - 1 + c _{1} x )}{2 x} ) 11}{2} + \frac{1}{2}

Solution steps

\frac{d y}{d x} x^{2} - y + y^{2} = - 3

Solve separable ODE:

y = \frac{tan ( - \frac{11 ( - 1 + c _{1} x )}{2 x} ) 11}{2} + \frac{1}{2}

y = \frac{tan ( - \frac{11 ( - 1 + c _{1} x )}{2 x} ) 11}{2} + \frac{1}{2}

y cos^{2} (x) \frac{d y}{d x} = 2 + tan (x)

(x^{3} + 1) \cdot y^{^{'}} = x^{2} \cdot y

y^{^{'}} = y^{3} \cdot e^{- x}

\frac{d y}{d t} = e^{t + y}, y (0) = 0

x y d x + (10 x y + x) d y = 0

What is the solution for (dy)/(dx)x^2-y+y^2=-3 ?
The solution for (dy)/(dx)x^2-y+y^2=-3 is y=(tan(-(sqrt(11)(-1+c_{1}x))/(2x))sqrt(11))/2+1/2