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Popular >

y^'y=y^2

Solution

y^{^{'}} y = y^{2}

Solution

y = e^{t + c_{1}}

Solution steps

y^{'} (t) y = y^{2}

Solve separable ODE:

y = e^{t + c_{1}}

y = e^{t + c_{1}}

Graph

Popular Examples

(dy}{dx}=\frac{sqrt(xy^2))/x

\frac{d y}{d x} = \frac{x y ^{2}}{x}

(2+cos(t))((dy)/(dt))-ysin(t)=0

(2 + cos (t)) (\frac{d y}{d t}) - y sin (t) = 0

ay^'=-by^2-c,y(0)=5

a y^{^{'}} = - b y^{2} - c, y (0) = 5

(dy)/(dx)y=x^{-3}6cos(x)

\frac{d y}{d x} y = x^{- 3} 6 cos (x)

(dy)/(dt)-y=1,y=0

\frac{d y}{d t} - y = 1, y = 0

Frequently Asked Questions (FAQ)

What is the solution for y^'y=y^2 ?
The solution for y^'y=y^2 is y=e^{t+c_{1}}