What is the solution for 1/y (dy)/(dx)=x^2+9 ?

The solution for 1/y (dy)/(dx)=x^2+9 is y=e^{(x^3)/3+9x+c_{1}}

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1/y (dy)/(dx)=x^2+9

\frac{1}{y} \frac{d y}{d x} = x^{2} + 9

y = e^{\frac{x ^{3}}{3} + 9 x + c_{1}}

Solution steps

\frac{1}{y} \frac{d y}{d x} = x^{2} + 9

Solve separable ODE:

y = e^{\frac{x ^{3}}{3} + 9 x + c_{1}}

y = e^{\frac{x ^{3}}{3} + 9 x + c_{1}}

\frac{d y}{d x} (y) = (csc (x) + cot (x))^{- 1}

\frac{d y}{d x} y = 6 arcsec (x + 5)

\frac{d y}{d t} = \frac{t + 3 t ^{2}}{y ^{2}}, y (0) = 6

\frac{d y}{d x} = \frac{x ^{2} + 1}{x y}

d y = (y + 1) (1 - x) d x, f (1) = 0

What is the solution for 1/y (dy)/(dx)=x^2+9 ?
The solution for 1/y (dy)/(dx)=x^2+9 is y=e^{(x^3)/3+9x+c_{1}}