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Popular >

area x,sqrt(x),[0,2]

Solution

area

x, x, [0, 2]

Solution

\frac{7 - 4 2}{3}

+1

Decimal Notation

0.44771 \dots

Solution steps

Apply the area formula:

\int_{0}^{2} x - x d x

Solve

\int_{0}^{2} x - x d x : \frac{7 - 4 2}{3}

The area is:

= \frac{7 - 4 2}{3}

Popular Examples

tangent of f(x)=sqrt(x^2-6x+25),\at x=0 tangent of

f (x) = x^{2} - 6 x + 25, at x = 0

tangent of f(x)=x^4+7e^x,(0,7)tangent of

f (x) = x^{4} + 7 e^{x}, (0, 7)

integral of (9sin^3(x))/(cos(x))

\int \frac{9 sin ^{3} ( x )}{cos ( x )} d x

limit as x approaches 5 of 5x-4

x \to 5 lim (5 x - 4)

integral from 1 to 2 of sqrt(1+1/(x^2))

\int_{1}^{2} 1 + \frac{1}{x ^{2}} d x

Frequently Asked Questions (FAQ)

What is area x,sqrt(x),[0,2] ?
The answer to area x,sqrt(x),[0,2] is (7-4sqrt(2))/3