What is the solution for y^'+12/280 y=3 ?

The solution for y^'+12/280 y=3 is y=-(e^{(-3t-c_{1})/(70)})/3+70

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y^'+12/280 y=3

y^{^{'}} + \frac{12}{280} y = 3

y = - \frac{e ^{\frac{- 3 t - c _{1}}{70}}}{3} + 70

Solution steps

y^{'} (t) + \frac{12}{280} y = 3

Solve separable ODE:

y = - \frac{e ^{\frac{- 3 t - c _{1}}{70}}}{3} + 70

y = - \frac{e ^{\frac{- 3 t - c _{1}}{70}}}{3} + 70

ln (y) d y = x y sin (x) d x

x^{^{'}} x = - \frac{1}{2} (x^{2} - 25)

x \frac{d y}{d x} = \frac{1 - 5 y ^{2}}{3 y}

x^{2} e^{y} \frac{d y}{d x} + 2 x e^{y} = x

\frac{y d y}{d x} + 4 x^{2} + 6 x + 1 = 0

What is the solution for y^'+12/280 y=3 ?
The solution for y^'+12/280 y=3 is y=-(e^{(-3t-c_{1})/(70)})/3+70