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Popular >

e^y*y^'=(3x^2)/(1+y)

Solution

e^{y} \cdot y^{^{'}} = \frac{3 x ^{2}}{1 + y}

Solution

y = W (x^{3} + c_{1})

Solution steps

e^{y} \cdot y^{'} (x) = \frac{3 x ^{2}}{1 + y}

Solve separable ODE:

y = W (x^{3} + c_{1})

y = W (x^{3} + c_{1})

Popular Examples

(dx)/(dt)=-x/(100)+125

\frac{d x}{d t} = - \frac{x}{100} + 125

x^'=-x^2,x(0)=5

x^{^{'}} = - x^{2}, x (0) = 5

(dy)/(dt)=y^2e^{-t},y(0)= 1/2 ,t>= 0

\frac{d y}{d t} = y^{2} e^{- t}, y (0) = \frac{1}{2}, t \geq 0

f(x)= 1/(1+x^2)f^'(x)

f (x) = \frac{1}{1 + x ^{2}} f^{^{'}} (x)

(dy)/(dx)=7xsec(y)

\frac{d y}{d x} = 7 x sec (y)

Frequently Asked Questions (FAQ)

What is the solution for e^y*y^'=(3x^2)/(1+y) ?
The solution for e^y*y^'=(3x^2)/(1+y) is y=\W(x^3+c_{1})