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Popular >

y^'=tan(x)y

Solution

y^{^{'}} = tan (x) y

Solution

y = \frac{c _{1}}{cos ( x )}

Solution steps

y^{'} (x) = tan (x) y

Solve separable ODE:

y = \frac{c _{1}}{cos ( x )}

y = \frac{c _{1}}{cos ( x )}

Popular Examples

(dy)/(dx)=e^{9y}+e^{(4x+9y)}

\frac{d y}{d x} = e^{9 y} + e^{(4 x + 9 y)}

y^'+4y=12,y(0)=0

y^{^{'}} + 4 y = 12, y (0) = 0

(dy)/(dx)+yln(x)=3ln(x)

\frac{d y}{d x} + y ln (x) = 3 ln (x)

(dy)/(dx)=(y(y+1))/(x+1)

\frac{d y}{d x} = \frac{y ( y + 1 )}{x + 1}

y^'=(1+y^6)/(xy^5),y(1)=1

y^{^{'}} = \frac{1 + y ^{6}}{x y ^{5}}, y (1) = 1

Frequently Asked Questions (FAQ)

What is the solution for y^'=tan(x)y ?
The solution for y^'=tan(x)y is y=(c_{1})/(cos(x))