What is the solution for y^'+(y^')/x+(1-1/(4x^2))y=0 ?

The solution for y^'+(y^')/x+(1-1/(4x^2))y=0 is y=e^{-x-1+c_{1}}\sqrt[4]{x^4+3x^3+3x^2+x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'+(y^')/x+(1-1/(4x^2))y=0

y^{^{'}} + \frac{y ^{^{'}}}{x} + (1 - \frac{1}{4 x ^{2}}) y = 0

y = e^{- x - 1 + c_{1}} 4 x^{4} + 3 x^{3} + 3 x^{2} + x

Solution steps

y^{'} (x) + \frac{y ^{'} ( x )}{x} + (1 - \frac{1}{4 x ^{2}}) y = 0

Solve separable ODE:

y = e^{- x - 1 + c_{1}} 4 x^{4} + 3 x^{3} + 3 x^{2} + x

y = e^{- x - 1 + c_{1}} 4 x^{4} + 3 x^{3} + 3 x^{2} + x

y y^{^{'}} - sin (x) = 0, y (π) = 1

csc (y) d y + sec^{2} (x) d x = 0

y^{^{'}} = \frac{3 x e ^{x}}{y 5 + y ^{2}}

2 y (y^{^{'}}) = 6 t^{2}

x ln (x) y^{^{'}} = y - 1

What is the solution for y^'+(y^')/x+(1-1/(4x^2))y=0 ?
The solution for y^'+(y^')/x+(1-1/(4x^2))y=0 is y=e^{-x-1+c_{1}}\sqrt[4]{x^4+3x^3+3x^2+x}