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Popular >

y^'+3y^'+2y=0

Solution

y^{^{'}} + 3 y^{^{'}} + 2 y = 0

Solution

y = e^{\frac{- t + c _{1}}{2}}

Solution steps

y^{'} (t) + 3 y^{'} (t) + 2 y = 0

Solve separable ODE:

y = e^{\frac{- t + c _{1}}{2}}

y = e^{\frac{- t + c _{1}}{2}}

Popular Examples

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[3 x cos (3 x) + sin (3 x) - 3] d x + (2 y + 5) d y = 0

Frequently Asked Questions (FAQ)

What is the solution for y^'+3y^'+2y=0 ?
The solution for y^'+3y^'+2y=0 is y=e^{(-t+c_{1})/2}