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Popular >

y^'=5e^{-x-y}

Solution

y^{^{'}} = 5 e^{- x - y}

Solution

y = ln (- 5 e^{- x} + c_{1})

Solution steps

y^{'} (x) = 5 e^{- x - y}

Solve separable ODE:

y = ln (- 5 e^{- x} + c_{1})

y = ln (- 5 e^{- x} + c_{1})

Popular Examples

(dy)/(dx)cos(y)+2xsin(y)=-2x

\frac{d y}{d x} cos (y) + 2 x sin (y) = - 2 x

(t^2-22t+85)(dy)/(dt)=y

(t^{2} - 22 t + 85) \frac{d y}{d t} = y

((dy)/(dx))=(-1/((x^2y^2))),y=2,x=1

(\frac{d y}{d x}) = (- \frac{1}{( x ^{2} y ^{2} )}), y = 2, x = 1

y^{^{'}} + \frac{1}{3} y = 0

y^'=sqrt(3)y,y(0)=14

y^{^{'}} = 3 y, y (0) = 14

Frequently Asked Questions (FAQ)

What is the solution for y^'=5e^{-x-y} ?
The solution for y^'=5e^{-x-y} is y=ln(-5e^{-x}+c_{1})