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Popular >

f^'(x)=-5f(x)

Solution

f^{^{'}} (x) = - 5 f (x)

Solution

f (x) = e^{- 5 x + c_{1}}

Solution steps

f^{'} (x) = - 5 f (x)

Solve separable ODE:

f (x) = e^{- 5 x + c_{1}}

f (x) = e^{- 5 x + c_{1}}

Popular Examples

y^'=(3x-e^x)/(2y-5)

y^{^{'}} = \frac{3 x - e ^{x}}{2 y - 5}

(1+y^2)cos(x)dx=2(1+sin^2(x))ydy

(1 + y^{2}) cos (x) d x = 2 (1 + sin^{2} (x)) y d y

y^'=((y-2)^2)/(x^2+1),y(0)=0

y^{^{'}} = \frac{( y - 2 ) ^{2}}{x ^{2} + 1}, y (0) = 0

(dy)/(dx)=(x+e^x)y

\frac{d y}{d x} = (x + e^{x}) y

y^'sqrt(x)=sqrt(y)cos(sqrt(x))

y^{^{'}} x = y cos (x)

Frequently Asked Questions (FAQ)

What is the solution for f^'(x)=-5f(x) ?
The solution for f^'(x)=-5f(x) is f(x)=e^{-5x+c_{1}}