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Popular >

-y^'-3y=0

Solution

- y^{^{'}} - 3 y = 0

Solution

y = e^{- 3 t + c_{1}}

Solution steps

- y^{'} (t) - 3 y = 0

Solve separable ODE:

y = e^{- 3 t + c_{1}}

y = e^{- 3 t + c_{1}}

Popular Examples

y^'=(2x^3)/(y^4),y(0)=3

y^{^{'}} = \frac{2 x ^{3}}{y ^{4}}, y (0) = 3

y^'= y/x-((y^2))/x

y^{^{'}} = \frac{y}{x} - \frac{( y ^{2} )}{x}

(e^{(-(2x-1))}(dy))/((dx))=e^{(-y)}

\frac{e ^{(- (2 x - 1))} ( d y )}{( d x )} = e^{(- y)}

y^{^{'}} + n^{2} y = b

(dV)/(dt)=50-7/100 V,V=0,t=0

\frac{d V}{d t} = 50 - \frac{7}{100} V, V = 0, t = 0

Frequently Asked Questions (FAQ)

What is the solution for -y^'-3y=0 ?
The solution for -y^'-3y=0 is y=e^{-3t+c_{1}}