What is the solution for y^{''}-12y^'+35y=e^{8x} ?

The solution for y^{''}-12y^'+35y=e^{8x} is y=c_{1}e^{7x}+c_{2}e^{5x}+1/3 e^{8x}

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y^{''}-12y^'+35y=e^{8x}

y^{^{''}} - 12 y^{^{'}} + 35 y = e^{8 x}

y = c_{1} e^{7 x} + c_{2} e^{5 x} + \frac{1}{3} e^{8 x}

Solution steps

y^{''} (x) - 12 y^{'} (x) + 35 y = e^{8 x}

Solve linear ODE:

y = c_{1} e^{7 x} + c_{2} e^{5 x} + \frac{1}{3} e^{8 x}

y = c_{1} e^{7 x} + c_{2} e^{5 x} + \frac{1}{3} e^{8 x}

y = \frac{7 x}{x}

x \to o lim (x)

\frac{\partial}{\partial t} (- 2 s t)

\int \frac{( 1 - x ) ^{2}}{2} d x

\int tan^{2} (x) + 1 d x

What is the solution for y^{''}-12y^'+35y=e^{8x} ?
The solution for y^{''}-12y^'+35y=e^{8x} is y=c_{1}e^{7x}+c_{2}e^{5x}+1/3 e^{8x}