What is the solution for y^{''}-2y^'-3y=4e^x-9 ?

The solution for y^{''}-2y^'-3y=4e^x-9 is y=c_{1}e^{3x}+c_{2}e^{-x}-e^x+3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-2y^'-3y=4e^x-9

y^{^{''}} - 2 y^{^{'}} - 3 y = 4 e^{x} - 9

y = c_{1} e^{3 x} + c_{2} e^{- x} - e^{x} + 3

Solution steps

y^{''} (x) - 2 y^{'} (x) - 3 y = 4 e^{x} - 9

Solve linear ODE:

y = c_{1} e^{3 x} + c_{2} e^{- x} - e^{x} + 3

y = c_{1} e^{3 x} + c_{2} e^{- x} - e^{x} + 3

y^{^{''}} - 10 y^{^{'}} + 9 y = 5 t, y (0) = - 1, y^{^{'}} (0) = 2

y^{^{''}} - 2 y^{^{'}} + 2 y = \frac{e ^{x}}{sin ( x )}

y^{^{''}} - y^{^{'}} = e^{x}

y^{^{''}} + 4 y^{^{'}} + 4 y = 8 e^{- 2 x}

y^{^{''}} - 8 y^{^{'}} + 16 y = e^{4 x} ln (9 + x^{2})

What is the solution for y^{''}-2y^'-3y=4e^x-9 ?
The solution for y^{''}-2y^'-3y=4e^x-9 is y=c_{1}e^{3x}+c_{2}e^{-x}-e^x+3