What is the solution for y^{''}-3y^'+2y=e^{-4t} ?

The solution for y^{''}-3y^'+2y=e^{-4t} is y=c_{1}e^{2t}+c_{2}e^t+1/30 e^{-4t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-3y^'+2y=e^{-4t}

y^{^{''}} - 3 y^{^{'}} + 2 y = e^{- 4 t}

y = c_{1} e^{2 t} + c_{2} e^{t} + \frac{1}{30} e^{- 4 t}

Solution steps

y^{''} (t) - 3 y^{'} (t) + 2 y = e^{- 4 t}

Solve linear ODE:

y = c_{1} e^{2 t} + c_{2} e^{t} + \frac{1}{30} e^{- 4 t}

y = c_{1} e^{2 t} + c_{2} e^{t} + \frac{1}{30} e^{- 4 t}

y^{^{''}} - 4 y^{^{'}} - 5 y = 2 e^{3 x}

y^{^{''}} - 5 y^{^{'}} + 6 y = x^{2}

y^{^{''}} - 4 y^{^{'}} - 12 y = 2 x + 6

y^{^{''}} + 4 y^{^{'}} + 4 y = x^{2} e^{- 2 x} + 1

y^{^{''}} - 4 y^{^{'}} + 4 y = x^{2} e^{2 x} - e^{2 x}

What is the solution for y^{''}-3y^'+2y=e^{-4t} ?
The solution for y^{''}-3y^'+2y=e^{-4t} is y=c_{1}e^{2t}+c_{2}e^t+1/30 e^{-4t}