What is the solution for y^{'''}-y^'=11t ?

The solution for y^{'''}-y^'=11t is y=c_{1}+c_{2}e^{-t}+c_{3}e^t-(11t^2)/2

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y^{'''}-y^'=11t

y^{^{'''}} - y^{^{'}} = 11 t

y = c_{1} + c_{2} e^{- t} + c_{3} e^{t} - \frac{11 t ^{2}}{2}

Solution steps

y^{'''} (t) - y^{'} (t) = 11 t

Solve linear ODE:

y = c_{1} + c_{2} e^{- t} + c_{3} e^{t} - \frac{11 t ^{2}}{2}

y = c_{1} + c_{2} e^{- t} + c_{3} e^{t} - \frac{11 t ^{2}}{2}

y^{^{''}} + 2 y^{^{'}} + y = \frac{e ^{- x}}{x}

y^{^{''}} - 4 y^{^{'}} = 1, y (0) = 1, y^{^{'}} (0) = 4

y^{^{''}} + 4 y = 4 sec (2 x)

y^{^{''}} - 2 y^{^{'}} + 2 y = 2 x - 2, y (π) = π, y (0) = 0

\frac{d ^{2} y}{d x ^{2}} + y = x^{2}

What is the solution for y^{'''}-y^'=11t ?
The solution for y^{'''}-y^'=11t is y=c_{1}+c_{2}e^{-t}+c_{3}e^t-(11t^2)/2