What is the solution for y^{''}-2y^'-3y=12e^x-6 ?

The solution for y^{''}-2y^'-3y=12e^x-6 is y=c_{1}e^{3x}+c_{2}e^{-x}-3e^x+2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-2y^'-3y=12e^x-6

y^{^{''}} - 2 y^{^{'}} - 3 y = 12 e^{x} - 6

y = c_{1} e^{3 x} + c_{2} e^{- x} - 3 e^{x} + 2

Solution steps

y^{''} (x) - 2 y^{'} (x) - 3 y = 12 e^{x} - 6

Solve linear ODE:

y = c_{1} e^{3 x} + c_{2} e^{- x} - 3 e^{x} + 2

y = c_{1} e^{3 x} + c_{2} e^{- x} - 3 e^{x} + 2

y^{^{''}} + y = x cos (x) - cos (x)

y^{^{''}} - 10 y^{^{'}} + 9 y = 5 t

y^{^{''}} - 4 y^{^{'}} + 4 y = x^{3} e^{2 x} + x e^{2 x}

y^{^{''}} - 2 y^{^{'}} + 2 y = e^{2 x} (cos (x) - 3 sin (x))

y^{^{''}} - 16 y^{^{'}} + 64 y = - \frac{2 e ^{8 x}}{3 x}

What is the solution for y^{''}-2y^'-3y=12e^x-6 ?
The solution for y^{''}-2y^'-3y=12e^x-6 is y=c_{1}e^{3x}+c_{2}e^{-x}-3e^x+2