What is the solution for y^{''}-3y^'-4y=2sin(x) ?

The solution for y^{''}-3y^'-4y=2sin(x) is y=c_{1}e^{4x}+c_{2}e^{-x}-5/17 sin(x)+3/17 cos(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-3y^'-4y=2sin(x)

y^{^{''}} - 3 y^{^{'}} - 4 y = 2 sin (x)

y = c_{1} e^{4 x} + c_{2} e^{- x} - \frac{5}{17} sin (x) + \frac{3}{17} cos (x)

Solution steps

y^{''} (x) - 3 y^{'} (x) - 4 y = 2 sin (x)

Solve linear ODE:

y = c_{1} e^{4 x} + c_{2} e^{- x} - \frac{5}{17} sin (x) + \frac{3}{17} cos (x)

y = c_{1} e^{4 x} + c_{2} e^{- x} - \frac{5}{17} sin (x) + \frac{3}{17} cos (x)

\frac{d ^{2} y}{d x ^{2}} + y = cos (x)

y^{^{''''}} + 2 y^{^{''}} + y = 3 + cos (2 t)

y^{^{''}} + 4 y = sin^{3} (x)

y^{^{''}} + 3 y^{^{'}} + 2 y = cos (t) - sin (2 t)

y^{^{''}} + 4 y = 8 sin (t)

What is the solution for y^{''}-3y^'-4y=2sin(x) ?
The solution for y^{''}-3y^'-4y=2sin(x) is y=c_{1}e^{4x}+c_{2}e^{-x}-5/17 sin(x)+3/17 cos(x)