What is the solution for y^{''}-3y^'+2y=sin(x) ?

The solution for y^{''}-3y^'+2y=sin(x) is y=c_{1}e^{2x}+c_{2}e^x+1/10 sin(x)+3/10 cos(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-3y^'+2y=sin(x)

y^{^{''}} - 3 y^{^{'}} + 2 y = sin (x)

y = c_{1} e^{2 x} + c_{2} e^{x} + \frac{1}{10} sin (x) + \frac{3}{10} cos (x)

Solution steps

y^{''} (x) - 3 y^{'} (x) + 2 y = sin (x)

Solve linear ODE:

y = c_{1} e^{2 x} + c_{2} e^{x} + \frac{1}{10} sin (x) + \frac{3}{10} cos (x)

y = c_{1} e^{2 x} + c_{2} e^{x} + \frac{1}{10} sin (x) + \frac{3}{10} cos (x)

y^{^{''}} - y = tan (x)

y^{^{''}} + y = 6 x sin (x)

y^{^{''}} + 6 y^{^{'}} + 13 y = 4 x^{2} - 5 x + 2 + 3 e^{x}

y^{^{''}} - 2 y^{^{'}} - 35 y = 13 sin (x) - e^{3 x} + 1

y^{^{''}} + 4 y = cos (x), y (0) = 6, y^{^{'}} (0) = - 6

What is the solution for y^{''}-3y^'+2y=sin(x) ?
The solution for y^{''}-3y^'+2y=sin(x) is y=c_{1}e^{2x}+c_{2}e^x+1/10 sin(x)+3/10 cos(x)