What is the solution for y^{''}-y=2e^x+2e^{-x}+x ?

The solution for y^{''}-y=2e^x+2e^{-x}+x is y=c_{1}e^x+c_{2}e^{-x}+e^xx-e^{-x}x-x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-y=2e^x+2e^{-x}+x

y^{^{''}} - y = 2 e^{x} + 2 e^{- x} + x

y = c_{1} e^{x} + c_{2} e^{- x} + e^{x} x - e^{- x} x - x

Solution steps

y^{''} (x) - y = 2 e^{x} + 2 e^{- x} + x

Solve linear ODE:

y = c_{1} e^{x} + c_{2} e^{- x} + e^{x} x - e^{- x} x - x

y = c_{1} e^{x} + c_{2} e^{- x} + e^{x} x - e^{- x} x - x

y^{^{''}} - 2 y^{^{'}} - 3 y = 4 e^{x} - 12

y^{^{''}} - 2 y^{^{'}} + 2 y = cos (t)

y^{^{''}} + y = \frac{2}{cos ( x )}

y^{^{''}} - 6 y^{^{'}} + 5 y = - 9 e^{2 x}

y^{^{''}} + 2 y^{^{'}} + y = e^{- t} t^{- 1}

What is the solution for y^{''}-y=2e^x+2e^{-x}+x ?
The solution for y^{''}-y=2e^x+2e^{-x}+x is y=c_{1}e^x+c_{2}e^{-x}+e^xx-e^{-x}x-x