What is the solution for y^{'''}-2y^{''}-y^'+2y=e^{7t} ?

The solution for y^{'''}-2y^{''}-y^'+2y=e^{7t} is y=c_{1}e^{2t}+c_{2}e^{-t}+c_{3}e^t+1/240 e^{7t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{'''}-2y^{''}-y^'+2y=e^{7t}

y^{^{'''}} - 2 y^{^{''}} - y^{^{'}} + 2 y = e^{7 t}

y = c_{1} e^{2 t} + c_{2} e^{- t} + c_{3} e^{t} + \frac{1}{240} e^{7 t}

Solution steps

y^{'''} (t) - 2 y^{''} (t) - y^{'} (t) + 2 y = e^{7 t}

Solve linear ODE:

y = c_{1} e^{2 t} + c_{2} e^{- t} + c_{3} e^{t} + \frac{1}{240} e^{7 t}

y = c_{1} e^{2 t} + c_{2} e^{- t} + c_{3} e^{t} + \frac{1}{240} e^{7 t}

y^{^{''}} + 3 y^{^{'}} - 18 y = - 66 t + 36 t^{2}

y^{^{''}} + 3 y^{^{'}} + 2 y = 4 x^{2}

y^{^{''}} + 2 y^{^{'}} + 5 y = 3 e^{- 2 t}

(D^{2} - 4 D + 13) y = 24 e^{2 x} cos (3 x)

y^{^{''}} - 2 y^{^{'}} + 10 y = 3 e^{x} tan (3 x)

What is the solution for y^{'''}-2y^{''}-y^'+2y=e^{7t} ?
The solution for y^{'''}-2y^{''}-y^'+2y=e^{7t} is y=c_{1}e^{2t}+c_{2}e^{-t}+c_{3}e^t+1/240 e^{7t}