What is the solution for y^{''}+9y=9sec(3x) ?

The solution for y^{''}+9y=9sec(3x) is y=c_{1}cos(3x)+c_{2}sin(3x)+ln(cos(3x))cos(3x)+3xsin(3x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+9y=9sec(3x)

y^{^{''}} + 9 y = 9 sec (3 x)

y = c_{1} cos (3 x) + c_{2} sin (3 x) + ln (cos (3 x)) cos (3 x) + 3 x sin (3 x)

Solution steps

y^{''} (x) + 9 y = 9 sec (3 x)

Solve linear ODE:

y = c_{1} cos (3 x) + c_{2} sin (3 x) + ln (cos (3 x)) cos (3 x) + 3 x sin (3 x)

y = c_{1} cos (3 x) + c_{2} sin (3 x) + ln (cos (3 x)) cos (3 x) + 3 x sin (3 x)

y^{^{''}} - 3 y^{^{'}} + 2 y = x

5 y^{^{''}} - 10 y^{^{'}} + 5 y = e^{x} ln (x)

y^{^{''}} + 5 y^{^{'}} + 6 y = 3 t^{2} + 4

y^{^{''}} + y = sec^{3} (x), y (0) = 1, y^{^{'}} (0) = \frac{1}{2}

y^{^{''}} - y = x^{2}

What is the solution for y^{''}+9y=9sec(3x) ?
The solution for y^{''}+9y=9sec(3x) is y=c_{1}cos(3x)+c_{2}sin(3x)+ln(cos(3x))cos(3x)+3xsin(3x)