What is the derivative of 2e^x+x ?

The derivative of 2e^x+x is 2e^x+1

What is the first derivative of 2e^x+x ?

The first derivative of 2e^x+x is 2e^x+1

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derivative of

2 e^{x} + x

2 e^{x} + 1

Solution steps

\frac{d}{d x} (2 e^{x} + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 e^{x}) + \frac{d x}{d x}

\frac{d}{d x} (2 e^{x}) = 2 e^{x}

\frac{d x}{d x} = 1

= 2 e^{x} + 1

\int_{3}^{\infty} e^{- 3 x} d x

y^{^{''}} - 2 y^{^{'}} + 82 y = 0

x \to 0 + lim ((1 + x)^{x})

x \to 0 + lim (tan (5 x) ln (8 x))

What is the derivative of 2e^x+x ?
The derivative of 2e^x+x is 2e^x+1
What is the first derivative of 2e^x+x ?
The first derivative of 2e^x+x is 2e^x+1