What is area y=4x^2,y=2\sqrt[3]{4} ?

The answer to area y=4x^2,y=2\sqrt[3]{4} is -(4sqrt(2))/3+4sqrt(2)

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area y=4x^2,y=2\sqrt[3]{4}

area

- \frac{4 2}{3} + 42

Decimal Notation

3.77123 \dots

Solution steps

Apply the area formula:

Solve

The area is:

= - \frac{4 2}{3} + 42

x \to \frac{1}{4} lim (tan (π x))

\frac{\partial}{\partial x} (e^{y x} \cdot sin (2 x y))

\int_{- \infty}^{0} 9^{r} d r

\int sin (x) + 36 - x^{2} d x

\frac{d}{d x} (\frac{6 x}{x + 3})

What is area y=4x^2,y=2\sqrt[3]{4} ?
The answer to area y=4x^2,y=2\sqrt[3]{4} is -(4sqrt(2))/3+4sqrt(2)