What is the derivative of (6x/(x+3)) ?

The derivative of (6x/(x+3)) is (18)/((x+3)^2)

What is the first derivative of (6x/(x+3)) ?

The first derivative of (6x/(x+3)) is (18)/((x+3)^2)

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\frac{d}{d x} (\frac{6 x}{x + 3})

\frac{18}{( x + 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{6 x}{x + 3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (\frac{x}{x + 3})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 6 \cdot \frac{\frac{d x}{d x} ( x + 3 ) - \frac{d}{d x} ( x + 3 ) x}{( x + 3 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x + 3) = 1

= 6 \cdot \frac{1 \cdot ( x + 3 ) - 1 \cdot x}{( x + 3 ) ^{2}}

Simplify

6 \cdot \frac{1 \cdot ( x + 3 ) - 1 \cdot x}{( x + 3 ) ^{2}} : \frac{18}{( x + 3 ) ^{2}}

= \frac{18}{( x + 3 ) ^{2}}

x^{6} + y^{5} x^{7} + 2 y^{^{'}} = 0

\frac{\partial}{\partial x} (x^{2} y^{3} z^{4})

\frac{d}{d x} (arccot (x - 1))

\frac{9 x}{x ^{2} + 5}

x \to \frac{π}{2} lim (\frac{tan ( 2 x )}{x - \frac{π}{2}})

What is the derivative of (6x/(x+3)) ?
The derivative of (6x/(x+3)) is (18)/((x+3)^2)
What is the first derivative of (6x/(x+3)) ?
The first derivative of (6x/(x+3)) is (18)/((x+3)^2)