Solution
Solution
Solution steps
Solve linear ODE:
Popular Examples
y^{''}+2y^'+y=2cos(2x)+3x+2+3e^xy^{''}+y=t^2sin(t),y(0)=0,y^'(0)=0y^{'''}-y^'=ty^{''}-y=1+e^xy^{''}+2y^'+y=(e^x-1)^{-2}
Frequently Asked Questions (FAQ)
What is the solution for y^{''}-y^'-2y=x ?
The solution for y^{''}-y^'-2y=x is y=c_{1}e^{2x}+c_{2}e^{-x}-x/2+1/4