What is the solution for y^{''}-16y=e^{4x} ?

The solution for y^{''}-16y=e^{4x} is y=c_{1}e^{4x}+c_{2}e^{-4x}+(e^{4x}x)/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-16y=e^{4x}

y^{^{''}} - 16 y = e^{4 x}

y = c_{1} e^{4 x} + c_{2} e^{- 4 x} + \frac{e ^{4 x} x}{8}

Solution steps

y^{''} (x) - 16 y = e^{4 x}

Solve linear ODE:

y = c_{1} e^{4 x} + c_{2} e^{- 4 x} + \frac{e ^{4 x} x}{8}

y = c_{1} e^{4 x} + c_{2} e^{- 4 x} + \frac{e ^{4 x} x}{8}

y^{^{'''}} - 2 y^{^{''}} - y^{^{'}} + 2 y = e^{8 t}

\frac{d ^{2} y}{d x ^{2}} - k \frac{d y}{d x} = x e^{x}

- 2 y^{^{''}} + y = e^{- 0.2 x}

2 y^{^{''}} - 6 y^{^{'}} + 3 y = 4 sin (x) + 6 x

4 y^{^{''}} - 4 y^{^{'}} + y = 56 e^{\frac{t}{2}}

What is the solution for y^{''}-16y=e^{4x} ?
The solution for y^{''}-16y=e^{4x} is y=c_{1}e^{4x}+c_{2}e^{-4x}+(e^{4x}x)/8